Génération de 89 sujets dans la boîte !

4 years ago · d0387aa5cb
parent fff20406d7
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+This is pdfTeX, Version 3.14159265-2.6-1.40.21 (MiKTeX 20.11) (preloaded format=pdflatex 2020.11.23)  5 NOV 2021 16:31
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--- a/Questions/BTS
+++ b/Questions/BTS
--- a/Questions/BTS
+++ b/Questions/BTS
@ -9,13 +9,16 @@
 \usepackage{amssymb}
 \usepackage{amsfonts}
 \usepackage{bbold}
 \usepackage{xcolor}
 \pagestyle{empty}
 \begin{document}
 \section*{Contrôle de Mathématiques}
-\let\MauvaiseReponse\null
+%\let\MauvaiseReponse\null
-\let\BonneReponse\null
+%\let\BonneReponse\null
 \def\MauvaiseReponse#1\par{\textcolor{red}{#1}}
 \def\BonneReponse#1\par{\textcolor{green}{#1}}
 {\bf Merci de répondre sur la grille fournie et de ne pas oublier de traiter les deux questions au verso en évitant de sortir des cadres. Vous prendrez soin de rendre le sujet avec cette grille.}
 \vspace{2em}
@ -30,82 +33,113 @@
 \item L'ensemble des solutions de l'inéquation $-2 x+2<1$ est :
 \begin{enumerate}
 \item\BonneReponse $]\frac{1}{2},+\infty[$
 \item\MauvaiseReponse $\mathbb{R}$
 \item\MauvaiseReponse $]-\infty, -\frac{1}{2}]$
 \end{enumerate}
 \item L'ensemble des solutions de l'inéquation $-2x+8 \geqslant 9$
 \begin{enumerate}
 \item\MauvaiseReponse $\mathbb{R}$
 \item\BonneReponse $]-\infty,-\frac{1}{2}]$
 \item\MauvaiseReponse $[-\frac{1}{2},+\infty[$
 \end{enumerate}
 \item Le nombre $\frac{1}{2}$
 \begin{enumerate}
 \item\MauvaiseReponse est solution de l'équation $x+2=0$
 \item\MauvaiseReponse est solution de l'équation $2x+1=0$
 \item\BonneReponse est solution de l'inéquation $3x+7>0$
 \end{enumerate}
 \item Le nombre $\sqrt{5}$
 \begin{enumerate}
 \item\BonneReponse est solution de l'équation $x^{3}-5x=0$
 \item\MauvaiseReponse est solution de l'inéquation $-5x+2>0$
 \item\MauvaiseReponse est solution de l'équation $x^{2}+5=0$
 \end{enumerate}
 \newpage
 \item Le nombre $\frac{1}{8}$
 \begin{enumerate}
 \item\BonneReponse est solution de l'équation $8x-1=0$
 \item\MauvaiseReponse est solution de l'équation $7x+1=0$
 \item\MauvaiseReponse est solution de l'inéquation $2x+7<0$
 \end{enumerate}
-\item Le couple solution du système $\left\{\begin{array}{c}5x+5y=10 \\ x-8y=-34\end{array}\right.$ est
+
 \item Le couple solution du système $\left\{\begin{array}{c}5x+5y=10 \\ x-8y=-34
 \end{array}\right.$ est
 \begin{enumerate}
 \item\MauvaiseReponse $(4;4)$
 \item\BonneReponse $(-2 ;4)$
 \item\MauvaiseReponse $(2 ; -2)$
 \end{enumerate}
@ -113,45 +147,60 @@
 \item $u$ est la suite définie pour tout entier $n \geqslant 1$ par $u_{n}=\frac{3n^{2}-2}{n^{2}}$.
 \begin{enumerate}
 \item\MauvaiseReponse $u_{3}=3$
 \item\BonneReponse $u_{3}=\frac{25}{9}$
 \item\MauvaiseReponse $u_{3} =\frac{79}{9}$
 \end{enumerate}
 \item Soit $\left(u_{n}\right)$ la suite définie par: $u_{0}=4$ et, pour tout entier naturel $n$, $u_{n+1}=3 u_{n}-1$, alors :
 \begin{enumerate}
 \item\MauvaiseReponse $u_{3}=4$
 \item\MauvaiseReponse $u_{3}=32$
 \item\BonneReponse $u_{3}=95$
 \end{enumerate}
 \newpage
 \item $v$ est la suite définie par $v_{0}=-2$ et la relation de récurrence\\ $v_{n+1}=5n-v_{n}$, alors :
 \begin{enumerate}
 \item\BonneReponse $v_{2}=3$
 \item\MauvaiseReponse $v_{2}=-5$
 \item\MauvaiseReponse $v_{2}=6$
 \end{enumerate}
@ -160,92 +209,124 @@
 \item On considère la suite arithmétique $\left(u_{n}\right)$ de premier terme $u_{0}=-4$\\ et de raison $r=-\frac{3}{4}$.
 \begin{enumerate}
 \item\MauvaiseReponse $u_{3}=-4$
 \item\MauvaiseReponse $u_{3}=-\frac{11}{2}$
 \item\BonneReponse $u_{3}=-\frac{25}{4}$
 \end{enumerate}
 \item Soit $\left(u_{n}\right)$ une suite géométrique de raison $q=\frac{2}{3}$. Sachant que $u_{3}=\frac{5}{8}$,\\ le premier terme $\mathrm{u}_ {0}$ est :
 \begin{enumerate}
 \item\BonneReponse $\frac{135}{64}$
 \item\MauvaiseReponse $\frac{5}{27}$
 \item\MauvaiseReponse $\frac{1024}{375}$
 \end{enumerate}
 \item Soit la suite $\left(u_{n}\right)$ définie par $u_{n+1}=\frac{2}{15}u_n$. Cette suite est :
 \begin{enumerate}
 \item\MauvaiseReponse croissante
 \item\BonneReponse décroissante
 \item\MauvaiseReponse constante
 \end{enumerate}
 \newpage
 \item On considère l'équation $4x^{2}-3 x-9=0$ alors le discriminant $\Delta$ est égal à :
 \begin{enumerate}
 \item\BonneReponse $153$
 \item\MauvaiseReponse $-135$
 \item\MauvaiseReponse $27$
 \end{enumerate}
 \item Le nombre de solutions de l'équation $3x^{2}-12 x+12=0$ est
 \begin{enumerate}
 \item\MauvaiseReponse $0$
 \item\BonneReponse $1$
 \item\MauvaiseReponse $2$
 \end{enumerate}
 \item L'ensemble des solutions de l'équation $x^{2}+4 x-45=0$ est :
 \begin{enumerate}
 \item\MauvaiseReponse $\emptyset$
 \item\BonneReponse $\{5 ;-9\}$
 \item\MauvaiseReponse $\{5 ; 9\}$
 \end{enumerate}
 \end{enumerate}
 \end{document}
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-Output written on "BTS 1 - DST 1 - Sujet B.pdf" (2 pages, 114370 bytes).
+Output written on "BTS 1 - DST 1 - Sujet B.pdf" (2 pages, 114509 bytes).
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--- a/Questions/BTS
+++ b/Questions/BTS
--- a/Questions/BTS
+++ b/Questions/BTS
@ -9,14 +9,17 @@
 \usepackage{amssymb}
 \usepackage{amsfonts}
 \usepackage{bbold}
 \usepackage{xcolor}
 \pagestyle{empty}
 \begin{document}
 \section*{Contrôle de Mathématiques}
-\let\MauvaiseReponse\null
+%\let\MauvaiseReponse\null
-\let\BonneReponse\null
+%\let\BonneReponse\null
 \def\MauvaiseReponse#1\par{\textcolor{red}{#1}}
 \def\BonneReponse#1\par{\textcolor{green}{#1}}
 {\bf Merci de répondre sur la grille fournie et de ne pas oublier de traiter les deux questions au verso en évitant de sortir des cadres. Vous prendrez soin de rendre le sujet avec cette grille.}
 \vspace{2em}
@ -93,6 +96,7 @@
 \begin{enumerate}
 \item\BonneReponse est solution de l'équation $8x-1=0$
 \item\MauvaiseReponse est solution de l'équation $7x+1=0$
@ -109,6 +113,7 @@
 \item\MauvaiseReponse $(6;4)$
 \item\BonneReponse $(-3 ;4)$
 \item\MauvaiseReponse $(2 ; -3)$
@ -127,6 +132,7 @@
 \item\MauvaiseReponse $u_{3} =\frac{32}{9}$
 \item\BonneReponse $u_{3}=-\frac{22}{9}$
 \end{enumerate}
@ -140,6 +146,7 @@
 \item\MauvaiseReponse $u_{3}=2$
 \item\BonneReponse $u_{3}=15$
 \item\MauvaiseReponse $u_{3}=6$
@ -155,6 +162,7 @@
 \item\MauvaiseReponse $v_{2}=-5$
 \item\BonneReponse $v_{2}=2$
 \item\MauvaiseReponse $v_{2}=5$
@ -170,6 +178,7 @@
 \item\MauvaiseReponse $u_{3}=-3$
 \item\BonneReponse $u_{3}=-\frac{9}{2}$
 \item\MauvaiseReponse $u_{3}=-4$
@ -183,6 +192,7 @@
 \item\MauvaiseReponse $\frac{5}{512}$
 \item\BonneReponse $40$
 \item\MauvaiseReponse $\frac{128}{125}$
@ -196,6 +206,7 @@
 \begin{enumerate}
 \item\BonneReponse décroissante
 \item\MauvaiseReponse croissante
@ -212,6 +223,7 @@
 \item\MauvaiseReponse $-47$
 \item\BonneReponse $97$
 \item\MauvaiseReponse $11$
@ -227,6 +239,7 @@
 \item\MauvaiseReponse $2$
 \item\BonneReponse $1$
 \end{enumerate}
@ -238,6 +251,7 @@
 \begin{enumerate}
 \item\BonneReponse $\{4 ;-7\}$
 \item\MauvaiseReponse $\emptyset$
--- a/Questions/BTS
+++ b/Questions/BTS
@ -1,4 +1,4 @@
-This is pdfTeX, Version 3.14159265-2.6-1.40.21 (MiKTeX 20.11) (preloaded format=pdflatex 2020.11.23)  27 OCT 2021 13:20
+This is pdfTeX, Version 3.14159265-2.6-1.40.21 (MiKTeX 20.11) (preloaded format=pdflatex 2020.11.23)  5 NOV 2021 16:45
 entering extended mode
 **"./BTS 1 - DST 1 - Sujet C.tex"
 ("BTS 1 - DST 1 - Sujet C.tex"
@ -126,6 +126,27 @@ LaTeX Font Info:    Redeclaring math symbol \hbar on input line 98.
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 File: color.cfg 2016/01/02 v1.6 sample color configuration
 )
 Package xcolor Info: Driver file: pdftex.def on input line 225.
 ("C:\Program Files\MiKTeX\tex/latex/graphics-def\pdftex.def"
 File: pdftex.def 2020/10/05 v1.2a Graphics/color driver for pdftex
 )
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 File: l3backend-pdftex.def 2020-09-24 L3 backend support: PDF output (pdfTeX)
 \l__kernel_color_stack_int=\count199
@ -134,20 +155,20 @@ File: l3backend-pdftex.def 2020-09-24 L3 backend support: PDF output (pdfTeX)
 ("BTS 1 - DST 1 - Sujet C.aux")
 \openout1 = `"BTS 1 - DST 1 - Sujet C.aux"'.
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+LaTeX Font Info:    Checking defaults for OML/cmm/m/it on input line 16.
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@ -183,12 +204,26 @@ LaTeX Font Info:    ... okay on input line 15.
 * \@reversemarginfalse
 * (1in=72.27pt=25.4mm, 1cm=28.453pt)
-LaTeX Font Info:    Trying to load font information for U+msa on input line 32.
+("C:\Program Files\MiKTeX\tex/context/base/mkii\supp-pdf.mkii"
 [Loading MPS to PDF converter (version 2006.09.02).]
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 \scratchbox=\box50
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 LaTeX Font Info:    Trying to load font information for U+msa on input line 35.
-("C:\Program Files\MiKTeX\tex/latex/amsfonts\umsa.fd"
+ ("C:\Program Files\MiKTeX\tex/latex/amsfonts\umsa.fd"
 File: umsa.fd 2013/01/14 v3.01 AMS symbols A
 )
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+LaTeX Font Info:    Trying to load font information for U+msb on input line 35.
 ("C:\Program Files\MiKTeX\tex/latex/amsfonts\umsb.fd"
@ -198,13 +233,13 @@ File: umsb.fd 2013/01/14 v3.01 AMS symbols B
 {C:/Users/Echophile/AppData/Local/MiKTeX/pdftex/config/pdftex.map}] [2] ("BTS 1
 - DST 1 - Sujet C.aux") ) 
 Here is how much of TeX's memory you used:
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+ 3267 strings out of 479799
- 30044 string characters out of 2879534
+ 41477 string characters out of 2879534
- 312987 words of memory out of 3000000
+ 329419 words of memory out of 3000000
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 539869 words of font info for 41 fonts, out of 3000000 for 9000
 1141 hyphenation exceptions out of 8191
- 66i,8n,72p,259b,174s stack positions out of 5000i,500n,10000p,200000b,50000s
+ 66i,8n,72p,259b,182s stack positions out of 5000i,500n,10000p,200000b,50000s
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@ -218,7 +253,7 @@ eX/fonts/type1/public/amsfonts/cm/cmsy10.pfb><C:/Program Files/MiKTeX/fonts/typ
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-Output written on "BTS 1 - DST 1 - Sujet C.pdf" (2 pages, 116481 bytes).
+Output written on "BTS 1 - DST 1 - Sujet C.pdf" (2 pages, 116623 bytes).
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--- a/Questions/BTS
+++ b/Questions/BTS
--- a/Questions/BTS
+++ b/Questions/BTS
@ -8,6 +8,7 @@
 \usepackage{amsmath}
 \usepackage{amssymb}
 \usepackage{amsfonts}
 \usepackage{xcolor}
 \pagestyle{empty}
@ -16,8 +17,10 @@
 \section*{Contrôle de Mathématiques}
-\let\MauvaiseReponse\null
+%\let\MauvaiseReponse\null
-\let\BonneReponse\null
+%\let\BonneReponse\null
 \def\MauvaiseReponse#1\par{\textcolor{red}{#1}}
 \def\BonneReponse#1\par{\textcolor{green}{#1}}
@ -37,6 +40,7 @@
 \item\MauvaiseReponse $]-\infty, \frac{1}{4}]$
 \item\BonneReponse $]-\frac{1}{4},+\infty[$
 \end{enumerate}
@ -53,6 +57,7 @@
 \item\MauvaiseReponse $\mathbb{R}$
 \item\BonneReponse $]-\infty,\frac{1}{5}]$
 \item\MauvaiseReponse $[\frac{1}{5},+\infty[$
@ -67,6 +72,7 @@
 \begin{enumerate}
 \item\MauvaiseReponse est solution de l'équation $4x+1=0$
 \item\BonneReponse est solution de l'inéquation $4x+5>0$
 \item\MauvaiseReponse est solution de l'équation $x+4=0$
@ -81,6 +87,7 @@
 \begin{enumerate}
 \item\BonneReponse est solution de l'équation $x^{3}-7x=0$
 \item\MauvaiseReponse est solution de l'équation $x^{2}+7=0$
@ -98,6 +105,7 @@
 \item\MauvaiseReponse est solution de l'inéquation $2x+3<0$
 \item\BonneReponse est solution de l'équation $10x-1=0$
 \end{enumerate}
@ -110,6 +118,7 @@
 \item\MauvaiseReponse $(6;-3)$
 \item\BonneReponse $(-3 ;-3)$
 \item\MauvaiseReponse $(-\frac{3}{2} ; -3)$
@ -130,6 +139,7 @@
 \item\MauvaiseReponse $u_{3} =\frac{77}{9}$
 \item\BonneReponse $u_{3}=-\frac{31}{9}$
 \end{enumerate}
@ -140,6 +150,7 @@
 \begin{enumerate}
 \item\BonneReponse $u_{3}=313$
 \item\MauvaiseReponse $u_{3}=3$
 \item\MauvaiseReponse $u_{3}=63$
@ -157,6 +168,7 @@
 \item\MauvaiseReponse $v_{2}=-6$
 \item\MauvaiseReponse $v_{2}=5$
 \item\BonneReponse $v_{2}=1$
 \end{enumerate}
@ -168,6 +180,7 @@
 \begin{enumerate}
 \item\BonneReponse $u_{3}=-7$
 \item\MauvaiseReponse $u_{3}=-5$
 \item\MauvaiseReponse $u_{3}=-\frac{19}{3}$
@ -185,6 +198,7 @@
 \item\MauvaiseReponse $\frac{4}{243}$
 \item\MauvaiseReponse $\frac{243}{64}$
 \item\BonneReponse $12$
 \end{enumerate}
@ -201,6 +215,7 @@
 \item\MauvaiseReponse constante
 \item\BonneReponse décroissante
 \end{enumerate}
@ -216,6 +231,7 @@
 \item\MauvaiseReponse $-80$
 \item\MauvaiseReponse $-28$
 \item\BonneReponse $208$
 \end{enumerate}
@ -227,6 +243,7 @@
 \begin{enumerate}
 \item\BonneReponse $1$
 \item\MauvaiseReponse $0$
@ -244,6 +261,7 @@
 \item\MauvaiseReponse $\{2 ; 9\}$
 \item\BonneReponse $\{2 ;-9\}$
 \end{enumerate}
--- a/Questions/TSP
+++ b/Questions/TSP
@ -0,0 +1,2 @@
 \relax 
 \gdef \@abspage@last{3}
--- a/Questions/TSP
+++ b/Questions/TSP
@ -0,0 +1,367 @@
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--- a/Questions/TSP
+++ b/Questions/TSP
--- a/Questions/TSP
+++ b/Questions/TSP
@ -10,7 +10,7 @@
 \usepackage{stmaryrd}
 \PassOptionsToPackage{version=3}{mhchem}
 \usepackage{mhchem}
-
+\usepackage{xcolor}
 \makeatletter
 %%%%%%%%%%%%%%%%%%%%%%%%%%%%%% User specified LaTeX commands.
 \usepackage{amsfonts}
@ -31,8 +31,11 @@
 \chapter*{Contrôle de Mathématiques}
-\let\MauvaiseReponse\null
+%\let\MauvaiseReponse\null
-\let\BonneReponse\null
+%\let\BonneReponse\null
 \def\MauvaiseReponse#1\par{\textcolor{red}{#1}}
 \def\BonneReponse#1\par{\textcolor{green}{#1}}
 {\bf Merci de répondre sur la grille fournie et de rendre le sujet avec la grille.}
 \vspace{2em}
@ -45,9 +48,13 @@
 \item L'ensemble des solutions de l'inéquation $-2 x+2<1$ est :
 \begin{enumerate}
 \item\BonneReponse $]\frac{1}{2},+\infty[$
 \item\MauvaiseReponse $\mathbb{R}$
 \item\MauvaiseReponse $]-\infty, -\frac{1}{2}]$
 \end{enumerate}
@ -59,6 +66,7 @@
 \item\BonneReponse $]-\infty,-\frac{1}{2}]$
 \item\MauvaiseReponse $[-\frac{1}{2},+\infty[$
 \end{enumerate}
@ -72,6 +80,7 @@
 \begin{enumerate}
 \item\MauvaiseReponse est solution de l'équation $x+2=0$
 \item\MauvaiseReponse est solution de l'équation $2x+1=0$
@ -89,6 +98,7 @@
 \item\BonneReponse est solution de l'équation $x^{3}-5x=0$
 \item\MauvaiseReponse est solution de l'inéquation $-5x+2>0$
 \item\MauvaiseReponse est solution de l'équation $x^{2}+5=0$
 \end{enumerate}
@ -101,6 +111,7 @@
 \item\BonneReponse est solution de l'équation $8x-1=0$
 \item\MauvaiseReponse est solution de l'équation $7x+1=0$
 \item\MauvaiseReponse est solution de l'inéquation $2x+7<0$
@ -117,6 +128,7 @@
 \item\MauvaiseReponse $(4;4)$
 \item\BonneReponse $(-2 ;4)$
 \item\MauvaiseReponse $(2 ; -2)$
@ -269,6 +281,7 @@
 \item\MauvaiseReponse $23\mathrm{cm}$
 \item\BonneReponse $40\mathrm{cm}$
 \item\MauvaiseReponse $50\mathrm{cm}$
@ -285,6 +298,7 @@
 \item\MauvaiseReponse $AB=24\mathrm{cm}$, $AC=34\mathrm{cm}$ et $BC=10\mathrm{cm}$
 \item\MauvaiseReponse $AB=24\mathrm{cm}$, $AC=14\mathrm{cm}$ et $BC=10\mathrm{cm}$
 \item\BonneReponse $AB=24\mathrm{cm}$, $AC=26\mathrm{cm}$ et $BC=10\mathrm{cm}$
 \end{enumerate}
@ -299,6 +313,7 @@
 \item\MauvaiseReponse $9\mathrm{cm}$
 \item\BonneReponse $16\mathrm{mm}$
 \item\MauvaiseReponse $36\mathrm{cm}$
 \end{enumerate}
@ -311,6 +326,7 @@
 \item\MauvaiseReponse $50\mathrm{mm}$
 \item\BonneReponse $80\mathrm{mm}$
 \item\MauvaiseReponse $50\mathrm{cm}$
--- a/Questions/TSP
+++ b/Questions/TSP
@ -0,0 +1,2 @@
 \relax 
 \gdef \@abspage@last{4}
--- a/Questions/TSP
+++ b/Questions/TSP
@ -0,0 +1,368 @@
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 PDF statistics:
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--- a/Questions/TSP
+++ b/Questions/TSP
--- a/Questions/TSP
+++ b/Questions/TSP
@ -10,6 +10,7 @@
 \usepackage{stmaryrd}
 \PassOptionsToPackage{version=3}{mhchem}
 \usepackage{mhchem}
 \usepackage{xcolor}
 \makeatletter
 %%%%%%%%%%%%%%%%%%%%%%%%%%%%%% User specified LaTeX commands.
@ -31,8 +32,10 @@
 \chapter*{Contrôle de Mathématiques}
-\let\MauvaiseReponse\null
+%\let\MauvaiseReponse\null
-\let\BonneReponse\null
+%\let\BonneReponse\null
 \def\MauvaiseReponse#1\par{\textcolor{red}{#1}}
 \def\BonneReponse#1\par{\textcolor{green}{#1}}
 {\bf Merci de répondre sur la grille fournie et de rendre le sujet avec la grille.}
 \vspace{2em}
@ -102,6 +105,7 @@
 \begin{enumerate}
 \item\BonneReponse est solution de l'équation $8x-1=0$
 \item\MauvaiseReponse est solution de l'équation $7x+1=0$
@ -118,6 +122,7 @@
 \item\MauvaiseReponse $(6;4)$
 \item\BonneReponse $(-3 ;4)$
 \item\MauvaiseReponse $(2 ; -3)$
@ -130,6 +135,7 @@
 \begin{enumerate}
 \item\BonneReponse $\{4 ;-6\}$
 \item\MauvaiseReponse $\emptyset$
@ -144,6 +150,7 @@
 \begin{enumerate}
 \item\MauvaiseReponse $\frac{23}{10}$
 \item\BonneReponse $-\frac{1}{10}$
 \item\MauvaiseReponse $\frac{23}{20}$
@ -159,6 +166,7 @@
 \item\MauvaiseReponse $\frac{72}{5}$
 \item\BonneReponse $\frac{32}{45}$
 \item\MauvaiseReponse $\frac{9}{10}$
@ -175,6 +183,7 @@
 \item\MauvaiseReponse $\cos (\hat{C})=\frac{2}{5}$
 \item\BonneReponse $AC=\sqrt{84}$
 \end{enumerate}
@ -188,6 +197,7 @@
 \item\MauvaiseReponse $\tan (\hat{C})=\frac{2}{7}$
 \item\BonneReponse $\cos (\hat{B})=\frac{2}{7}$
 \item\MauvaiseReponse $AC=\sqrt{212}$
@ -200,6 +210,7 @@
 \begin{enumerate}
 \item\BonneReponse $\arctan\left(\frac{35}{20}\right)$
 \item\MauvaiseReponse $20\times\arctan\left(35\right)$
@ -230,6 +241,7 @@
 \item\MauvaiseReponse $\widehat{C}=40^{\circ}$
 \item\BonneReponse $\widehat{C}=30^{\circ}$
 \item\MauvaiseReponse $\widehat{C}=15^{\circ}$
@ -245,6 +257,7 @@
 \item\MauvaiseReponse $47\mathrm{cm}$
 \item\BonneReponse $37\mathrm{cm}$
 \item\MauvaiseReponse $23\mathrm{cm}$
 \end{enumerate}
@ -259,6 +272,7 @@
 \item\MauvaiseReponse $47\mathrm{cm}$
 \item\MauvaiseReponse $98\mathrm{cm}$
 \item\BonneReponse $84\mathrm{cm}$
 \end{enumerate}
@ -299,6 +313,7 @@
 \item\MauvaiseReponse $12\mathrm{mm}$
 \item\BonneReponse $750\mathrm{mm}$
 \item\MauvaiseReponse $12\mathrm{cm}$
@ -315,6 +330,7 @@
 \item\MauvaiseReponse $AB=21\mathrm{m}$, $AC=84\mathrm{m}$, $A^{\prime}B^{\prime}=49\mathrm{cm}$ et $A^{\prime}C^{\prime}=36\mathrm{cm}$
 \item\BonneReponse $AB=21\mathrm{m}$, $AC=84\mathrm{m}$, $A^{\prime}B^{\prime}=49\mathrm{cm}$ et $A^{\prime}C^{\prime}=196\mathrm{cm}$
 \item\MauvaiseReponse $AB=21\mathrm{m}$, $AC=84\mathrm{m}$, $A^{\prime}B^{\prime}=49\mathrm{cm}$ et $A^{\prime}C^{\prime}=9\mathrm{cm}$
--- a/Questions/TSP
+++ b/Questions/TSP
@ -0,0 +1,2 @@
 \relax 
 \gdef \@abspage@last{3}
--- a/Questions/TSP
+++ b/Questions/TSP
@ -0,0 +1,367 @@
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--- a/Questions/TSP
+++ b/Questions/TSP
--- a/Questions/TSP
+++ b/Questions/TSP
@ -10,6 +10,7 @@
 \usepackage{stmaryrd}
 \PassOptionsToPackage{version=3}{mhchem}
 \usepackage{mhchem}
 \usepackage{xcolor}
 \makeatletter
 %%%%%%%%%%%%%%%%%%%%%%%%%%%%%% User specified LaTeX commands.
@ -31,8 +32,10 @@
 \chapter*{Contrôle de Mathématiques}
-\let\MauvaiseReponse\null
+%\let\MauvaiseReponse\null
-\let\BonneReponse\null
+%\let\BonneReponse\null
 \def\MauvaiseReponse#1\par{\textcolor{red}{#1}}
 \def\BonneReponse#1\par{\textcolor{green}{#1}}
 {\bf Merci de répondre sur la grille fournie et de rendre le sujet avec la grille.}
@ -50,6 +53,7 @@
 \item\MauvaiseReponse $]-\infty, \frac{1}{4}]$
 \item\BonneReponse $]-\frac{1}{4},+\infty[$
 \end{enumerate}
@ -66,6 +70,7 @@
 \item\MauvaiseReponse $\mathbb{R}$
 \item\BonneReponse $]-\infty,\frac{1}{5}]$
 \item\MauvaiseReponse $[\frac{1}{5},+\infty[$
@ -80,6 +85,7 @@
 \begin{enumerate}
 \item\MauvaiseReponse est solution de l'équation $4x+1=0$
 \item\BonneReponse est solution de l'inéquation $4x+5>0$
 \item\MauvaiseReponse est solution de l'équation $x+4=0$
@ -94,6 +100,7 @@
 \begin{enumerate}
 \item\BonneReponse est solution de l'équation $x^{3}-7x=0$
 \item\MauvaiseReponse est solution de l'équation $x^{2}+7=0$
@ -111,6 +118,7 @@
 \item\MauvaiseReponse est solution de l'inéquation $2x+3<0$
 \item\BonneReponse est solution de l'équation $10x-1=0$
 \end{enumerate}
@ -124,6 +132,7 @@
 \item\MauvaiseReponse $(6;-3)$
 \item\BonneReponse $(-3 ;-3)$
 \item\MauvaiseReponse $(-\frac{3}{2} ; -3)$
@ -151,6 +160,7 @@
 \begin{enumerate}
 \item\BonneReponse $-\frac{23}{14}$
 \item\MauvaiseReponse $-\frac{11}{14}$
 \item\MauvaiseReponse $-\frac{11}{28}$
@ -168,6 +178,7 @@
 \item\MauvaiseReponse $52$
 \item\BonneReponse $\frac{44}{9}$
 \item\MauvaiseReponse $\frac{99}{16}$
 \end{enumerate}
@ -183,6 +194,7 @@
 \item\MauvaiseReponse $\cos (\hat{C})=\frac{1}{5}$
 \item\BonneReponse $AC=\sqrt{384}$
 \end{enumerate}
@ -194,6 +206,7 @@
 \begin{enumerate}
 \item\BonneReponse $\cos (\hat{B})=\frac{3}{5}$
 \item\MauvaiseReponse $\tan (\hat{C})=\frac{3}{5}$
 \item\MauvaiseReponse $AC=\sqrt{136}$
@ -211,6 +224,7 @@
 \item\MauvaiseReponse $\frac{\arctan\left(\frac{7}{2}\right)}{4}$
 \item\BonneReponse $\arctan\left(\frac{35}{40}\right)$
 \end{enumerate}
@ -224,6 +238,7 @@
 \item\MauvaiseReponse $\widehat{C}=70^{\circ}$
 \item\BonneReponse $\widehat{C}=60^{\circ}$
 \item\MauvaiseReponse $\widehat{C}=75^{\circ}$
@ -268,6 +283,7 @@
 \item\MauvaiseReponse $98\mathrm{cm}$
 \item\MauvaiseReponse $200\mathrm{cm}$
 \item\BonneReponse $180\mathrm{cm}$
 \end{enumerate}
@ -280,6 +296,7 @@
 \item\MauvaiseReponse $AB=99\mathrm{cm}$, $AC=119\mathrm{cm}$ et $BC=20\mathrm{cm}$
 \item\BonneReponse $AB=99\mathrm{cm}$, $AC=101\mathrm{cm}$ et $BC=20\mathrm{cm}$
 \item\MauvaiseReponse $AB=99\mathrm{cm}$, $AC=79\mathrm{cm}$ et $BC=20\mathrm{cm}$
@ -296,6 +313,7 @@
 \item\MauvaiseReponse $20\mathrm{cm}$
 \item\MauvaiseReponse $8\mathrm{cm}$
 \item\BonneReponse $18\mathrm{mm}$
 \end{enumerate}
@ -311,6 +329,7 @@
 \item\MauvaiseReponse $50\mathrm{mm}$
 \item\BonneReponse $80\mathrm{mm}$
 \item\MauvaiseReponse $50\mathrm{cm}$
 \end{enumerate}
@ -327,6 +346,7 @@
 \item\MauvaiseReponse $AB=21\mathrm{m}$, $AC=42\mathrm{m}$, $A^{\prime}B^{\prime}=49\mathrm{cm}$ et $A^{\prime}C^{\prime}=18\mathrm{cm}$
 \item\MauvaiseReponse $AB=21\mathrm{m}$, $AC=42\mathrm{m}$, $A^{\prime}B^{\prime}=49\mathrm{cm}$ et $A^{\prime}C^{\prime}=9\mathrm{cm}$
 \item\BonneReponse $AB=21\mathrm{m}$, $AC=42\mathrm{m}$, $A^{\prime}B^{\prime}=49\mathrm{cm}$ et $A^{\prime}C^{\prime}=98\mathrm{cm}$
 \end{enumerate}
--- a/elm-stuff/0.19.1/ParserTest.elmi
+++ b/elm-stuff/0.19.1/ParserTest.elmi
--- a/elm-stuff/0.19.1/ParserTest.elmo
+++ b/elm-stuff/0.19.1/ParserTest.elmo
--- a/elm-stuff/0.19.1/QCM.elmi
+++ b/elm-stuff/0.19.1/QCM.elmi
--- a/elm-stuff/0.19.1/QCM.elmo
+++ b/elm-stuff/0.19.1/QCM.elmo
--- a/elm-stuff/0.19.1/d.dat
+++ b/elm-stuff/0.19.1/d.dat
--- a/elm-stuff/0.19.1/i.dat
+++ b/elm-stuff/0.19.1/i.dat
--- a/elm-stuff/0.19.1/o.dat
+++ b/elm-stuff/0.19.1/o.dat
--- a/elm.json
+++ b/elm.json
@ -10,6 +10,8 @@
            "elm/core": "1.0.5",
            "elm/html": "1.0.0",
            "elm/parser": "1.1.0",
            "elm/random": "1.0.0",
            "elm-community/random-extra": "3.2.0",
            "lynn/elm-arithmetic": "3.0.0"
        },
        "indirect": {
--- a/src/ParserArbre.elm
+++ b/src/ParserArbre.elm
@ -0,0 +1,164 @@
 module ParserArbre exposing (..)
 import Parser exposing (..)
 import Browser
 import Html exposing (Html, button, div, text)
 import Html.Events exposing (onClick)
 import Maybe exposing (Maybe)
 import Result exposing (Result)
 -- MAIN
 main =
  Browser.sandbox { init = init, update = update, view = view }
 -- MODEL
 type alias Model = Int
 init : Model
 init =
  0
 -- UPDATE
 type Msg
  = Increment
  | Decrement
 update : Msg -> Model -> Model
 update msg model =
  case msg of
    Increment ->
      model + 1
    Decrement ->
      model - 1
 -- VIEW
 view : Model -> Html Msg
 view model =
  div [] [ text texte ]
 {-
  Sans le withIndent -1, les arbres sous-indentés sautes
 -}
 texte = voirArbresParses <| run (withIndent -1 arbres)
  """
  *
    *
    *
      *
      *
      *
        *
        *
      *
        *
      *
 *
      *
      *
      *
  *
 *
  *
 """
 unArbre =
  Arbre
    [ Arbre []
    , Arbre
      [ Arbre []
      ]
    ]
 voirArbresParses arbresParsesPotentiels =
  case arbresParsesPotentiels of
    Err erreurs -> deadEndsToStringBis erreurs
    Ok arbresParses -> voirArbres arbresParses
 deadEndsToStringBis errs =
  errs
  |> List.map voirErreur
  |> String.concat
  |> (++) "Il y a des problèmes aux endroits suivants :\n"
 voirErreur err =
  "Ligne : " ++ String.fromInt err.row
  ++ " | Colonne : " ++ String.fromInt err.col
 type Arbre = Arbre (List Arbre)
 voirArbre arbr =
  case arbr of
    Arbre [] -> "[]"
    Arbre arbrs -> "[" ++ String.concat (List.map voirArbre arbrs) ++ "]"
 voirArbres =
  List.map voirArbre >> String.concat
 {-| Ce parser change l'indentation courante, cré un arbre puis
  y intègre ses branches grâce à une boucle
 -}
 arbre : Parser Arbre
 arbre =
  let
    suite =
      Debug.log "? :" <|
      flip withIndent
        <| succeed Arbre
          |. symbol "*"
          |= arbres
  in
  getCol
  |> andThen suite
  |> Debug.log "Arbre : "
 flip f a b = f b a
 arbres =
  let
    sousArbres arbrs =
      let
        boucle =
          succeed ( \arbr -> Loop (arbr :: arbrs) )
            |= arbre -- lazy (\_ -> arbre) semble inutile malgrè l'appel récursif...
        fin =
          map (\_ -> Done (List.reverse arbrs))
        suite col_ind =
          oneOf
            [ succeed ()
                |. end
              |> fin
            , if Tuple.first col_ind > Tuple.second col_ind then -- if col > ind
                boucle
              else
                succeed ()
                |> fin
             ]
      in
      succeed Tuple.pair
      |. spaces
      |= getCol
      |= getIndent
      |> andThen suite
  in
  loop [] sousArbres
  |> Debug.log "Début de la boucle arbres : "
--- a/src/ParserTest.elm
+++ b/src/ParserTest.elm
@ -1,11 +1,15 @@
 module ParserTest exposing (..)
-import Parser exposing (..)
+import Parser as P exposing (..)
 import Browser
 import Html exposing (Html, button, div, text)
 import Html.Events exposing (onClick)
 import Maybe exposing (Maybe)
 import Result exposing (Result)
 import String as S
 import List as L
 import ParserMaths as PM
 import Fractions as F exposing (Frac)
@ -53,14 +57,25 @@ update msg model =
 view : Model -> Html Msg
 view model =
-  div [] [ text texte ]
+  div [] [ text unTexte ]
-
+{-
-texte = voirArbresParses <| run (withIndent -1 arbres) -- permet d'avoir...
+  Sans le withIndent -1, les arbres sous-indentés sautes
 -}
 unTexte = voirArbresParses <| run (withIndent -1 arbres)
 {--}
  """
  macro
   hh
 jj
  """
 --}
 {--
  """
  *
    *
-    *
+    #1+3#
      *
      *
      *
@ -69,19 +84,15 @@ texte = voirArbresParses <| run (withIndent -1 arbres) -- permet d'avoir...
      *
        *
      *
-*                  <- cet arbre
+  *
      *
      *
      *
-"""
+  *
-
+  *
-unArbre =
+  *
-  Arbre
+  """
-    [ Arbre []
+--}
    , Arbre
      [ Arbre []
      ]
    ]
 voirArbresParses arbresParsesPotentiels =
  case arbresParsesPotentiels of
@ -98,12 +109,12 @@ voirErreur err =
  "Ligne : " ++ String.fromInt err.row
  ++ " | Colonne : " ++ String.fromInt err.col
-type Arbre = Arbre (List Arbre)
+type Arbre = Arbre String (List Arbre)
 voirArbre arbr =
  Debug.log "voirArbre " <|
  case arbr of
-    Arbre [] -> "[]"
+    Arbre chn arbrs -> chn ++ "\n  [" ++ String.concat (List.map voirArbre arbrs) ++ "]"
    Arbre arbrs -> "[" ++ String.concat (List.map voirArbre arbrs) ++ "]"
 voirArbres =
  List.map voirArbre >> String.concat
@ -115,13 +126,15 @@ arbre : Parser Arbre
 arbre =
  let
    suite =
      Debug.log "? :" <|
      flip withIndent
        <| succeed Arbre
-          |. symbol "*"
+          |= chaine
          |= arbres
  in
  getCol
  |> andThen suite
  |> Debug.log "Arbre : "
 flip f a b = f b a
@ -131,7 +144,7 @@ arbres =
      let
        boucle =
          succeed ( \arbr -> Loop (arbr :: arbrs) )
-            |= lazy (\_ -> arbre)
+            |= arbre -- lazy (\_ -> arbre) semble inutile malgrè l'appel récursif...
        fin =
          map (\_ -> Done (List.reverse arbrs))
        suite col_ind =
@ -152,4 +165,58 @@ arbres =
      |= getIndent
      |> andThen suite
  in
-  loop [] sousArbres
+  loop [] sousArbres
  |> Debug.log "Début de la boucle arbres "
 {-
 ██████   █████  ██████  ███████ ███████ ██████      ███    ███  █████   ██████ ██████   ██████  
 ██   ██ ██   ██ ██   ██ ██      ██      ██   ██     ████  ████ ██   ██ ██      ██   ██ ██    ██ 
 ██████  ███████ ██████  ███████ █████   ██████      ██ ████ ██ ███████ ██      ██████  ██    ██ 
 ██      ██   ██ ██   ██      ██ ██      ██   ██     ██  ██  ██ ██   ██ ██      ██   ██ ██    ██ 
 ██      ██   ██ ██   ██ ███████ ███████ ██   ██     ██      ██ ██   ██  ██████ ██   ██  ██████  
 -}
 chaine : Parser String
 chaine =
  let
    suite txt =
      P.oneOf
        [ succeed (\x -> P.Loop (txt ++ x))
            |= texte
            {--
            |= P.oneOf
              [ texte
              , retourAlaLigne
              ]
            --}
        , succeed ()
            --|. token "\n"
            |> P.map (\_ -> P.Done [txt])
        ]
    tete ls =
      case ls of
        [] -> ""
        l :: lss -> l
  in
  succeed tete
  |= P.loop "" suite
  |> Debug.log "macro "
 texte : Parser String
 texte =
  P.getChompedString
  <| succeed ()
    |. P.chompIf ( (/=) '\n' )
    |. P.chompWhile ( (/=) '\n' )
 retourAlaLigne : Parser String
 retourAlaLigne =
  let
    suite ind =
      succeed "\n"
        |. token "\n"
        |. token (S.repeat ind " ")
  in
  getIndent
  |> andThen suite
--- a/src/QCM.elm
+++ b/src/QCM.elm
@ -1,15 +1,49 @@
 module QCM exposing (..)
 import Browser
-import Parser as P exposing (Parser, (|.), (|=), succeed, symbol, float, spaces)
+import Parser as P exposing (..)
 {--
  ( Parser
  , (|.)
  , (|=)
  , succeed
  , symbol
  , float
  , spaces
  , token
  , loop
  , getIndent
  , andThen
  , oneOf
  , Step
  )
 --}
 import List as L
 import Set
 import ParserMaths as PM
 import String as S
 import Fractions as F exposing (Frac)
 import Html exposing (Html, Attribute, button, div, textarea, input, p, iframe, section)
-import Html.Attributes exposing (..)
+import Html.Attributes as A -- exposing (..)
 import Html.Events exposing (onInput, onClick)
 import Random
 import Random.Extra
 sujetTest =
  """a : 2,4
 b : 3,5,8
  c : 6,7,9
   On considère l'équation $#a#x^{2}-#b# x-#c#=0$ alors 
   le discriminant $\\Delta$ est égal à :
    vrfx
     +$#b^2+4*a*c#$
     -$#b^2-4*a*c#$
  """
 {-
        ███    ███  █████  ██ ███    ██ 
@ -20,7 +54,12 @@ import Html.Events exposing (onInput, onClick)
 -}
 main =
-  Browser.sandbox { init = init, update = update, view = view }
+  Browser.element
    { init = init
    , update = update
    , subscriptions = subscriptions
    , view = view
    }
 {-
@ -32,19 +71,22 @@ main =
 -}
 type alias Model =
-  { variables : String
+  { -- variables : String
-  , question : String
+    structureDuSujet : String
-  , questions : List String
+  -- , questions : List String
  , sujetGenere : String
  }
-init : Model
+init : () -> (Model, Cmd Msg)
-init =
+init _ =
-  { variables = ""
+  ( { -- variables = ""
-  , question = ""
+      structureDuSujet = ""
-  , questions = [ "" ]
+    -- , questions = []
-  }
+    , sujetGenere = ""
-
+    }
  , Cmd.none
  )
 {-
        ██    ██ ██████  ██████   █████  ████████ ███████ 
@ -55,19 +97,47 @@ init =
 -}
 type Msg
-  = Question String
+  = StructureDuSujet String
-  | Variables String
+  -- | Variables String
-  | GenererQuestion
+  | GenererSujet
  | SujetGenere String 
-update : Msg -> Model -> Model
+update : Msg -> Model -> ( Model, Cmd Msg )
 update msg model =
  case msg of
-    Question nouvelleQuestion ->
+    StructureDuSujet nouvelleStructure ->
-      { model | question = nouvelleQuestion }
+      ( { model | structureDuSujet = nouvelleStructure }
      , Cmd.none
      )
    {--
    Variables nouvellesVariables ->
-      { model | variables = nouvellesVariables }
+      ( { model | variables = nouvellesVariables }
-    GenererQuestion ->
+      , Cmd.none
-      { model | questions = remplacer model.variables model.question }
+      )
    --}
    SujetGenere nouveauSujetGenere ->
      ( { model | sujetGenere = nouveauSujetGenere }
      , Cmd.none
      )
    GenererSujet ->
      let
        f strSuj =
          case P.run (withIndent -1 sujet) strSuj of
            Ok sjt -> Random.map quizScanVoirSujet <| sujetsAleatoires sjt
            Err erreurs -> Random.constant <| deadEndsToStringBis erreurs
      in
      ( model
      , Random.generate SujetGenere (f model.structureDuSujet)
      )
 -- SUBSCRIPTIONS
 subscriptions : Model -> Sub Msg
 subscriptions model =
  Sub.none
 {-
@ -81,10 +151,12 @@ update msg model =
 view : Model -> Html Msg
 view model =
  div []
-    <| textarea [ placeholder "Liste des variables", value model.variables, onInput Variables ] []
+    <| -- textarea [ A.placeholder "Liste des variables", A.value model.variables, onInput Variables ] []
-    :: textarea [ placeholder "Format de la question", value model.question, onInput Question ] []
+    textarea [ A.placeholder "Structure du sujet", A.value model.structureDuSujet, onInput StructureDuSujet ] []
-    :: button [ onClick GenererQuestion ] [ text "Générer les questions" ]
+    -- :: button [ onClick GenererQuestion ] [ text "Générer les questions" ]
-    ::  ( section [] <| L.map (\q -> p [] [text q]) model.questions ) 
+    :: button [ onClick GenererSujet ] [ text "Générer un sujet au hasard" ]
    -- ::  ( section [] <| L.map (\q -> p [] [ text q ]) model.questions )
    ::  [ ( section [] [ p [] [ text model.sujetGenere ] ] ) ]
    {--
    :: text
      (
@ -132,9 +204,7 @@ view model =
    , List.map dl03 ( mix [ [0], [-9,-8,-7,-6,-5,-4,-3,-2,-1,1,2,3,4,5,6,7,8,9], [0], [1,2,3,4,5,6,7,8,9] ] )  -- 162 possibilités OK
    , List.map dl04 ( mix [ [-5,-3,-1,1,3,5], [-6,-4,-2,2,4,6], [0], [-9,-8,-7,-6,-5,-4,-3,-2,-1] ] )  --324 possibilités Ok
    , List.concat <| List.map ( mapTwist [3,5,9] ) ( List.map dl05 ( mix [ [0], [2,4,7,8,11,13,16,17], [2,4,7,8,11,13,16,17] ] ) )  -- 192 possibilités OK
    --}
    :: d3 -- 512 possibilités OK
    {--
    :: ( List.map primitPoly01 <| mix [ List.range -3 -2 ++ List.range 2 3, List.range -3 -2 ++ List.range 2 3, List.range -3 -2 ++ List.range 2 3, List.range -3 -2 ++ List.range 2 3 ] ) -- 256 possibilités OK
 -- mix [ [1,2] , [3,4] , [5,6] ] == [ [1,3,5] , [1,3,6] , [1,4,5] , [1,4,6] , [2,3,5] , ... ]
 mix lls =
@ -152,11 +222,200 @@ text chaine =
 {-
-        ██████   █████  ██████  ███████ ███████ ██████       ██████   ██████ ███    ███ 
+██████   █████  ██████  ███████ ███████ ██████      ███████ ██    ██      ██ ███████ ████████ 
-        ██   ██ ██   ██ ██   ██ ██      ██      ██   ██     ██    ██ ██      ████  ████ 
+██   ██ ██   ██ ██   ██ ██      ██      ██   ██     ██      ██    ██      ██ ██         ██    
-        ██████  ███████ ██████  ███████ █████   ██████      ██    ██ ██      ██ ████ ██ 
+██████  ███████ ██████  ███████ █████   ██████      ███████ ██    ██      ██ █████      ██    
-        ██      ██   ██ ██   ██      ██ ██      ██   ██     ██ ▄▄ ██ ██      ██  ██  ██ 
+██      ██   ██ ██   ██      ██ ██      ██   ██          ██ ██    ██ ██   ██ ██         ██    
-        ██      ██   ██ ██   ██ ███████ ███████ ██   ██      ██████   ██████ ██      ██ 
+██      ██   ██ ██   ██ ███████ ███████ ██   ██     ███████  ██████   █████  ███████    ██    
 -}
 type alias Sujet = List Probleme
 type Probleme =
  VariableAremplacer Aremplacer Sujet
  | Entete Macro Sujet
  -- | ProblemeOuvert NombreDeLigne TexteVariable
  -- | QCM Propositions
  | VraiFaux Propositions
 type alias Propositions = List Proposition
 type Proposition =
  Vrai Macro
  | Faux Macro
 type alias NombreDeLigne = Int
 type alias Alternative =
  { vraies : List Macro
  , fausses : List Macro
  }
 {--
 voirSujetParse sujetPotentiel =
  case P.run (withIndent -1 sujet) sujetPotentiel of
    Ok sjt -> voirSujet sjt
    Err erreurs -> deadEndsToStringBis erreurs
 --}
 voirSujetParseAleatoire sujetPotentiel =
  case P.run (withIndent -1 sujet) sujetPotentiel of
    Ok sjt -> Random.map quizScanVoirSujet <| sujetAleatoire sjt
    Err erreurs -> Random.constant <| deadEndsToStringBis erreurs
 deadEndsToStringBis errs =
  errs
  |> List.map voirErreur
  |> String.concat
  |> (++) "Il y a des problèmes aux endroits suivants :\n"
 voirErreur err =
  "Ligne : " ++ String.fromInt err.row
  ++ " | Colonne : " ++ String.fromInt err.col
 {--
 voirSujet = S.join "\n" << L.map voirProbleme
 voirProbleme prblm =
  -- Debug.log "voirProbleme " <|
  case prblm of
    Entete mcr sjt ->
      voirMacro mcr
      ++ "\n"
      ++ voirSujet sjt
    VraiFaux prps ->
      let
        f prp =
          case prp of
            Vrai mcr -> voirMacro mcr
            Faux mcr -> voirMacro mcr
      in
      S.join "\n" <| L.map f prps
    VariableAremplacer ar sjt -> "" ++ voirSujet sjt
 --}
 sujet : Parser Sujet
 sujet =
  let
    problemes prblms =
      let
        boucle =
          -- Debug.log "Boucle sur un probleme (bis) " <|
          succeed ( \prblm -> Loop (prblm :: prblms) )
            |= probleme
        fin =
          map (\_ -> Done (List.reverse prblms))
        suite col_ind =
          oneOf
            [ succeed ()
                |. end
              |> fin
            , if Tuple.first col_ind > Tuple.second col_ind then -- if col > ind
                boucle -- |> Debug.log "Boucle sur un probleme "
              else
                succeed ()
                |> fin
             ]
          -- |> Debug.log ( "Choix de l'embrachement dans la boucle (position " ++ S.fromInt (Tuple.first col_ind) ++ "x" ++ S.fromInt (Tuple.second col_ind) ++ ")" )
      in
      succeed Tuple.pair
      |. spaces
      |= getCol
      |= getIndent
      |> andThen suite
  in
  loop [] problemes
 probleme : Parser Probleme
 probleme =
  let
    suite =
      flip withIndent
        <| oneOf
          [ vraiFaux
          , backtrackable variableAremplacer
          , entete ]
  in
  getCol
  |> andThen suite
 flip f a b = f b a
 reserve = Set.fromList
  [ "qcm"
  , "vrfx"
  , "var"
  ]
 sousSujet =
  let
    suite col_ind =
      if Tuple.first col_ind > Tuple.second col_ind then -- if col > ind
        withIndent (Tuple.first col_ind) ( lazy (\_ -> sujet) ) -- Aucune idée de l'effet du lazy, ça marche sans...
      else
        succeed []
  in
  succeed Tuple.pair
  |. spaces
  |= getCol
  |= getIndent
  |> andThen suite
 entete : Parser Probleme
 entete =
  -- Debug.log "entete " <|
  succeed Entete
    |= macro
    |= sujet -- sousSujet
 vraiFaux =
  -- Debug.log "vraiFaux " <|
  succeed VraiFaux
    |. keyword "vrfx"
    |= propositions
 propositions =
  let
    suiteBis prps =
      let
        boucle =
          oneOf
            [ succeed ( \mcr -> Loop ( Vrai mcr :: prps ) )
                |. symbol "+"
                |= macro
            , succeed ( \mcr -> Loop ( Faux mcr :: prps ) )
                |. symbol "-"
                |= macro
            ]
        fin =
          map (\_ -> Done prps)
        suite col_ind =
          oneOf
            [ succeed ()
                |. end
              |> fin
            , if Tuple.first col_ind > Tuple.second col_ind then -- if col > ind
                boucle
              else
                succeed ()
                |> fin
             ]
      in
      succeed Tuple.pair
      |. spaces
      |= getCol
      |= getIndent
      |> andThen suite
  in
  loop [] suiteBis
 {-
 ██████   █████  ██████  ███████ ███████ ██████      ███    ███  █████   ██████ ██████   ██████  
 ██   ██ ██   ██ ██   ██ ██      ██      ██   ██     ████  ████ ██   ██ ██      ██   ██ ██    ██ 
 ██████  ███████ ██████  ███████ █████   ██████      ██ ████ ██ ███████ ██      ██████  ██    ██ 
 ██      ██   ██ ██   ██      ██ ██      ██   ██     ██  ██  ██ ██   ██ ██      ██   ██ ██    ██ 
 ██      ██   ██ ██   ██ ███████ ███████ ██   ██     ██      ██ ██   ██  ██████ ██   ██  ██████  
 -}
 type TexteVariable
@ -166,14 +425,14 @@ type TexteVariable
 type alias Macro
  = List TexteVariable
-voirMacro macro
+voirMacro = S.concat << L.map voirTexteVariable
  = S.concat <| L.map voirTexteVariable macro
-voirTexteVariable txtvar
+voirTexteVariable txtvar =
-  = case txtvar of
+  case txtvar of
    Texte txt -> txt
    Variable var ->
-      let expressionParseePotentielle = PM.parseMaths var
+      let
        expressionParseePotentielle = PM.parseMaths var
      in
      case expressionParseePotentielle of
        Err erreur -> "L'expression est mal formée."
@ -183,12 +442,16 @@ voirTexteVariable txtvar
            Nothing -> "Les puissances non-entières ne sont pas acceptées."
 texteSansVariables : Parser TexteVariable
-texteSansVariables
+texteSansVariables =
-  = succeed Texte
+  let
    condition caractere = caractere /= '#' && caractere /= '\n'
  in
  succeed Texte
  |= P.getChompedString (
    succeed ()
-    |. P.chompIf ( (/=) '#' )
+    |. P.chompIf condition
-    |. P.chompWhile ( (/=) '#' )
+    |. P.chompWhile condition
  )
 expressionVariable : Parser TexteVariable
@ -198,23 +461,32 @@ expressionVariable
  |= P.getChompedString ( P.chompUntil "#" )
  |. symbol "#"
-parserQuestion question =
+macro : Parser Macro
-  case P.run questions question of
+macro =
-    Ok macro -> macro
+  let
-    Err _ -> []
+    suite ls =
-
+      P.oneOf
-questions : Parser Macro
+        [ succeed (\l -> P.Loop (l :: ls))
-questions =
+            |= P.oneOf
-  P.loop [] questionsBis
+              [ expressionVariable
-
+              , texteSansVariables
-questionsBis : Macro -> Parser (P.Step Macro Macro)
+              , backtrackable retourAlaLigne
-questionsBis ls =
+              ]
-  P.oneOf
+        , succeed ()
-    [ succeed (\l -> P.Loop (l :: ls))
+            |> P.map (\_ -> P.Done (List.reverse ls))
-        |= P.oneOf [ expressionVariable , texteSansVariables ]
+        ]
-    , succeed ()
+  in
-        |> P.map (\_ -> P.Done (List.reverse ls))
+  P.loop [] suite
-    ]
+
 retourAlaLigne =
  let
    suite ind =
      succeed (Texte "\n")
        |. token "\n"
        |. token (S.repeat (ind - 1) " ")
  in
  getIndent
  |> andThen suite
 {-
@ -225,6 +497,8 @@ questionsBis ls =
        ██      ██   ██ ██   ██ ███████ ███████ ██   ██       ████   ██   ██ ██   ██ 
 -}
 type alias Variables = List Aremplacer
 type alias Aremplacer =
  { var : String
  , vals : List String
@ -235,33 +509,156 @@ parserAremplacer variables =
          Ok ars -> ars
          Err _ -> Aremplacer "" []
 espaces =
  chompWhile <| (==) ' '
 variableAremplacer : Parser Probleme
 variableAremplacer =
  -- Debug.log "variableAremplacer " <|
  succeed VariableAremplacer
    |= aRemplacer
    |= sujet -- sousSujet
 aRemplacer : Parser Aremplacer
 aRemplacer =
  succeed ( \x y -> Aremplacer x (L.map (F.raw << PM.evaluerBis) y) )
-  |. P.spaces
+    |. espaces
-  |= P.variable
+    |= variable
-    { start = \_ -> True
+      { start = Char.isAlpha
-    , inner = Char.isAlpha
+      , inner = Char.isAlpha
-    , reserved = Set.fromList []
+      , reserved = reserve
-    }
+      }
-  |. P.spaces
+    |. espaces
-  |. P.symbol ":"
+    |. symbol ":"
-  |= P.sequence
+    |= sequence
-    { start = ""
+      { start = ""
-    , separator = ","
+      , separator = ","
-    , end = ""
+      , end = ""
-    , spaces = spaces
+      , spaces = espaces
-    , item = PM.expr
+      , item = PM.expr
-    {--
+      , trailing = P.Optional
    , item = P.variable
      { start = (/=) ','
      , inner = (/=) ','
      , reserved = Set.fromList []
      }
    --}
    , trailing = P.Optional
    }
 {-
 ███████      ██ ████████      █████  ██      ███████  █████  ████████  ██████  ██ ██████  ███████ 
 ██           ██    ██        ██   ██ ██      ██      ██   ██    ██    ██    ██ ██ ██   ██ ██      
 ███████      ██    ██        ███████ ██      █████   ███████    ██    ██    ██ ██ ██████  █████   
     ██ ██   ██    ██        ██   ██ ██      ██      ██   ██    ██    ██    ██ ██ ██   ██ ██      
 ███████  █████     ██        ██   ██ ███████ ███████ ██   ██    ██     ██████  ██ ██   ██ ███████ 
 -}
 sujetsAleatoires : Sujet -> Random.Generator Sujet
 sujetsAleatoires sjt =
  sujetAleatoire sjt
  |> Random.list 89
  |> Random.map L.concat
 sujetAleatoire : Sujet -> Random.Generator Sujet
 sujetAleatoire sjt =
  Random.map L.concat
  <| Random.Extra.sequence
  <| L.map problemeAleatoire sjt
 problemeAleatoire : Probleme -> Random.Generator Sujet
 problemeAleatoire prblm =
  case prblm of
    VariableAremplacer ar sjt ->
      let
        vrbl = ar.var
        vlr = valeurAleatoire "" ar.vals
        f sj vl = remplacerLaVariableDansLeSujetAleatoire vrbl vl sj
      in
      {--
      Debug.log
        ( "problemeAleatoire, branche VariableAremplacer, variable : "
          ++ vrbl ++ " "
        ) <|
      --}
      Random.andThen (f sjt) vlr
    Entete mcr sjt ->
      Random.map (L.singleton << Entete mcr) (sujetAleatoire sjt)
    VraiFaux prps -> propositionAleatoire prps
 propositionAleatoire prps =
  Random.map
    (L.singleton << VraiFaux << L.singleton)
    ( valeurAleatoire ( Vrai [ Texte "Le prof de maths est le meilleur." ] ) prps )
 {-| Permet de prendre un élément aléatoire dans une liste
    avec une valeur par défaut si la liste est vide.
 -}
 valeurAleatoire : a -> List a -> Random.Generator a
 valeurAleatoire f fs =
  case fs of
    [] ->
      Random.constant f
    ff :: fss ->
      Random.uniform ff fss
 remplacerLaVariableDansLeProblemeAleatoire :
  String -> String -> Probleme -> Random.Generator Sujet
 remplacerLaVariableDansLeProblemeAleatoire vrbl vlr prblm =
  case prblm of
    VariableAremplacer ar sjt ->
      problemeAleatoire (VariableAremplacer ar sjt)
      |> Random.andThen (remplacerLaVariableDansLeSujetAleatoire vrbl vlr)
    Entete mcr sjt ->
      Random.map L.singleton
      <| Random.map2 Entete
          ( Random.constant <| remplacerLaVariableParLaValeurDansLaMacro vrbl vlr mcr )
          ( remplacerLaVariableDansLeSujetAleatoire vrbl vlr sjt )
    VraiFaux prps ->
      Random.map
        ( L.singleton
          << VraiFaux
          << L.singleton
          << remplacerLaVariableParLaValeurDansLaProposition vrbl vlr
        )
        <| valeurAleatoire ( Vrai [ Texte "Le prof de maths est le meilleur." ] ) prps
 remplacerLaVariableDansLeSujetAleatoire :
  String -> String -> Sujet -> Random.Generator Sujet
 remplacerLaVariableDansLeSujetAleatoire vrbl vlr sjt =
  Random.map L.concat
  <| Random.Extra.sequence
  <| L.map (remplacerLaVariableDansLeProblemeAleatoire vrbl vlr) sjt
 remplacerLaVariableParLaValeurDansLaProposition vrbl vlr prp =
  case prp of
    Vrai mcr -> Vrai <| remplacerLaVariableParLaValeurDansLaMacro vrbl vlr mcr
    Faux mcr -> Faux <| remplacerLaVariableParLaValeurDansLaMacro vrbl vlr mcr
 {-
         ██████  ██    ██ ██ ███████ ███████  ██████  █████  ███    ██ 
        ██    ██ ██    ██ ██    ███  ██      ██      ██   ██ ████   ██ 
        ██    ██ ██    ██ ██   ███   ███████ ██      ███████ ██ ██  ██ 
        ██ ▄▄ ██ ██    ██ ██  ███         ██ ██      ██   ██ ██  ██ ██ 
         ██████   ██████  ██ ███████ ███████  ██████ ██   ██ ██   ████ 
            ▀▀                                                         
 -}
 quizScanVoirSujet : Sujet -> String
 quizScanVoirSujet sjt =
  S.join "\n" <| L.map quizScanVoirProbleme sjt
 quizScanVoirProbleme prblm =
  case prblm of
    Entete mcr sjt ->
      voirMacro mcr
      ++ "\n"
      ++ quizScanVoirSujet sjt
    VraiFaux prps ->
      let
        f prp =
          case prp of
            Vrai mcr ->
              "  \\item\\Vrai{" ++ voirMacro mcr ++ "}\n"
            Faux mcr ->
              "  \\item\\Faux{" ++ voirMacro mcr ++ "}\n"
      in
      S.join "\n" <| L.map f prps
    VariableAremplacer ar sjt -> "" ++ quizScanVoirSujet sjt
 {-
        ███    ███ ██ ██   ██ ███████ ██    ██ ██████  
        ████  ████ ██  ██ ██  ██      ██    ██ ██   ██ 
@ -270,20 +667,21 @@ aRemplacer =
        ██      ██ ██ ██   ██ ███████  ██████  ██   ██ 
 -}
 {--
 remplacer : String -> String -> List String
 remplacer variables question =
  let
    ars =
      S.lines variables
      |> L.map parserAremplacer
-    macro =
+    mcr =
      parserQuestion question
  in
-  remplacerLesVariablesDansLaMacro ars macro
+  remplacerLesVariablesDansLaMacro ars mcr
 remplacerLesVariablesDansLaMacro : List Aremplacer -> Macro -> List String
-remplacerLesVariablesDansLaMacro ars macro =
+remplacerLesVariablesDansLaMacro ars mcr =
-  remplacerLesVariablesDansLaMacroBis ars [macro]
+  remplacerLesVariablesDansLaMacroBis ars [mcr]
  |> L.map voirMacro
 remplacerLesVariablesDansLaMacroBis : List Aremplacer -> List Macro -> List Macro
@ -296,20 +694,23 @@ remplacerLesVariablesDansLaMacroBis ars macros =
      |> remplacerLesVariablesDansLaMacroBis arss
 remplacerLaVariableDansLaMacro : Aremplacer -> Macro -> List Macro
-remplacerLaVariableDansLaMacro ar macro =
+remplacerLaVariableDansLaMacro ar mcr =
  let
-    f val = remplacerLaVariableParLaValeurDansLaMacro ar.var val macro
+    f val = remplacerLaVariableParLaValeurDansLaMacro ar.var val mcr
  in  
  L.map f ar.vals 
 --}
 remplacerLaVariableParLaValeurDansLaMacro : String -> String -> Macro -> Macro
-remplacerLaVariableParLaValeurDansLaMacro var val macro =
+remplacerLaVariableParLaValeurDansLaMacro var val mcr =
-  L.map (remplacerLaVariableParLaValeurDansLeTexteVariable var val) macro
+  L.map (remplacerLaVariableParLaValeurDansLeTexteVariable var val) mcr
 remplacerLaVariableParLaValeurDansLeTexteVariable var val tv =
  case tv of
    Texte chaine -> Texte chaine
    Variable chaine -> Variable <| S.replace var val chaine
 --}
 {-